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Bohrov model atoma (TEK U IZRADI! NE UPOTREBLJAVATI!)


 \begin{displaymath}\oint p_{\theta} d \theta = n \hbar
\end{displaymath} (1.68)


 \begin{displaymath}E = \frac {1}{2} m v^{2} - \frac {e^{2}}{r} = \frac
{p^{2}_{\theta}}{2 mr^{2}} - \frac {e^{2}}{r}
\end{displaymath} (1.70)


 \begin{displaymath}\frac {m v^{2}}{r} = \frac {p^{2}_{\theta}}{m r^{3}} = \frac
{e^{2}}{r^{2}}
\end{displaymath} (1.71)


 \begin{displaymath}\frac {e^{2}}{r} = \frac {p^{2}_{\theta}}{m r^{2}} = \frac
{n^{2}\hbar^{2}}{mr^{2}} (\hbar \equiv \frac {\hbar}{2 \pi})
\end{displaymath} (1.72)


 \begin{displaymath}r_{n} = \frac {n^{2} \hbar^{2}}{m e^{2}}
\end{displaymath} (1.73)


\begin{displaymath}E_{n} = - \frac {p^{2}_{\theta}}{2 mr^{2}} = - \frac {n^{2}
\hbar^{2}}{2m} (\frac {me^{2}}{n^{2} \hbar^{2}})^{2}
\end{displaymath} (1.74)


 \begin{displaymath}= - \frac {R}{n^{2}}
\end{displaymath} (1.75)


 \begin{displaymath}R= \frac {m^{4}_{e}}{2 \hbar^{2}} = 2.18 \times 10^{-11} erg = 13.6
eV
\end{displaymath} (1.76)


 \begin{displaymath}r_{1} \equiv a_{0} \frac {\hbar^{2}}{me^{2}} = 5.29 \times 10^{-9} cm
\end{displaymath} (1.77)


next up previous
Next: About this document ... Up: Začeci kvantne fizike Previous: Comptonov efekt
Dubravko Klabucar
2000-11-10